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Low output from older, but unused panels
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I will add for the anecdote, that during cloud edge effect (bright sunny days with passing clouds when the sun crosses the edge of the cloud), I have seen these panel reach 340Watts (30 V x 11.33A) or 110% of ISCLeave a comment:
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My panels are 320W Silfab.(max power 32.88V x 9.74A, ISC 10.32A) they are installed full south at 20degree pitch in north California.
In the best spring summer days they will reach 300 watts (10A x 30 Volts.
Right now on the best days they only reach 230Watts (7.4 A x 31 Volts) or 71% of ISCLeave a comment:
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My panels are 320W Silfab.(max power 32.88V x 9.74A, ISC 10.32A) they are installed full south at 20degree pitch in north California.
In the best spring summer days they will reach 300 watts (10A x 30 Volts.
Right now on the best days they only reach 230Watts (7.4 A x 31 Volts) or 71% of ISC
Leave a comment:
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This is not rocket science but your lack of understanding of what's actual required is making you think or wish things are simpler than they actually are.
GIGO applies here.
There is no such thing as "what is expected" with respect to short circuit current or other panel operating parameters such as voltage or circuit temp. except what you calculate from the operating conditions and other inputs that affect those outputs.
The conditions that control a panel's output parameters are hardly ever equal to those at standard test conditions. On site you measure the Isc and compare that to the calculated Isc using measured P.O.A. irradiance, cell temp. and maybe some other stuff depending on required precision while making sure the panel is clean.
Then, compare those results to the panel's STC parameters to get some estimate of the panels' current performance.
Take what you want of the above. Scrap the rest.Leave a comment:
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If testing by manually aiming a panel directly at the sun on a clear day, then, no. If already mounted at a less than perfect angle for today's sun elevation, then, could be.Last edited by littleharbor2; 12-12-2022, 07:11 AM.Leave a comment:
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To find the information you're looking for you will need to know the rate of energy input to a solar panel (that is, the plane of array or "P.O.A." irradiance) while simultaneously measuring the output of the panel, either the power output in watts or the voltage and current. The panel instantaneous efficiency will be the output divided by the input.
Given the season, time of day, solar position and other variables including the big and apriori unknowable atmospheric conditions which are constantly changing, you won't have much of a chance to see 1,000 W/m^2 normal (that is, perpendicular) plane of array irradiance on a PV panel.
Without ways of measuring at least the P.O.A. irradiance, the panel cell temps. and the panel output you won't be able to estimate the instantaneous panel efficiency and so whether or not there is a problem with the panels.
My tested ISC is about 60% of the rated ISC. Is that expected in the northern US, mid-December?Leave a comment:
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Thanks but I'm not sure what to do with this advice. How can I determine the instantaneous irradiance during my test? The only info I've seen uses average irradiance over a day, and that would include the losses due to shorter days, not just the seasonal reduction in the strength of the sun.
Given the season, time of day, solar position and other variables including the big and apriori unknowable atmospheric conditions which are constantly changing, you won't have much of a chance to see 1,000 W/m^2 normal (that is, perpendicular) plane of array irradiance on a PV panel.
Without ways of measuring at least the P.O.A. irradiance, the panel cell temps. and the panel output you won't be able to estimate the instantaneous panel efficiency and so whether or not there is a problem with the panels.Leave a comment:
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T400H, STC 11.14 and NMOT 8.97.
And for reference, back in June those values were NE 9.18A, SE 9.87A, and SW/NW 9.83A at peak.Leave a comment:
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My NE panels peaked at 3.94A, SE at 7.55A, and SW/NW at 5.56A. Voltage was 35-36V.Leave a comment:
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Were your friends panels tilted up and toward the sun. I can't imagine full output from panels lying flat on a van's roof at this time of year. There must be some factor keeping your panels from reading higher current. Are they being shaded at all by a hand holding the panel while angling it toward the sun? You will only get max current when the orientation is perfect. This can be viewed on the meter while manually changing the tilt.Leave a comment:
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Thanks but I'm not sure what to do with this advice. How can I determine the instantaneous irradiance during my test? The only info I've seen uses average irradiance over a day, and that would include the losses due to shorter days, not just the seasonal reduction in the strength of the sun.Leave a comment:
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I would expect the voltage to increase with cold, the current
not to change much. That current is pretty low, but do be
sure you are really getting full sun. The slighest haze or
cloud will have considerable effect, and the slighest smoke
(from all those fires) is even more devastating.
I would want to at least have another comparable orientation
panel to see how it is doing, before writing off the used panels.
good luck, Bruce RoeLeave a comment:
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Without knowing what the irradiance is when you're measuring a panel's output you will have no way to measure/estimate/compare what a panel's performance is compared to its 1,000 W/m^2 STC irradiance measurement.Leave a comment:
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