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  • SunEagle
    replied
    Originally posted by bcroe
    Just to muddy the waters some more, I'd like to suggest that the inverters working harder and subject
    to clipping might have a higher failure rate. That is inconvenient and costs a lot, esp with labor thrown
    in. That said, I am working on destroying my inverters with clipping, no problemo yet. Bruce Roe
    What helps electronics and reduces failure rates due to "over working" can be related to how well the hardware is cooled. Working hard isn't the problem. NOT getting rid of the damaging heat is.

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  • bcroe
    replied
    Originally posted by J.P.M.
    To a greater or lesser extent, that depends on the cost of the electricity not produced. If say, 200 kWh/yr. is clipped at $0.20/kWh, 40 bucks/yr. in lost opportunity may or may not be significant to the owner(s). clipping loss will need to be evaluated and a value assigned to it.

    71SoCal: Tilt/azimuth/zip ?
    Just to muddy the waters some more, I'd like to suggest that the inverters working harder and subject
    to clipping might have a higher failure rate. That is inconvenient and costs a lot, esp with labor thrown
    in. That said, I am working on destroying my inverters with clipping, no problemo yet. Bruce Roe

    Leave a comment:


  • logdin
    replied
    Originally posted by 71SoCal
    Yes, it's really just a math problem. I would definitely appreciate any "real world" data. My location info: zip is 92128, roof tilt is 18.5 deg., azimuth is 240 deg. One panel will shadow partially during the day (north side of fireplace).
    If you want real world, we're practically neighbors. I have LG260s with M250's. I've never clipped my 250s, but would have if I had 215s. I've seen 242 on my 260's this year. There's one more thing I factored in (guestimated). M250's = 3rd generation. M215's = 2nd generation. Newer technology "may" bring higher reliability. Time will only tell.

    After FTC you are talking less than $350 difference. I have 235 azimuth with minor shading in 92129 at 22 degrees. Are you east or west of I15? my sig is my PVOutput system. If you get a login, and PM me, I'll give you trusted user access for a bit. I have per panel monitoring too on enphase so you can see that too.

    If you stick with Enphase, IMHO I'd pick the newer technology and take advantage of maximum production.

    My 1 cents worth.

    Leave a comment:


  • J.P.M.
    replied
    Originally posted by NVEnergyLLC
    Are there REC incentives? Mass is $0.33/kwh (last quarter)
    Not for residential in CA at this time. Stay tuned.

    Leave a comment:


  • NVEnergyLLC
    replied
    Originally posted by 71SoCal
    Yes, it's really just a math problem. I would definitely appreciate any "real world" data. My location info: zip is 92128, roof tilt is 18.5 deg., azimuth is 240 deg. One panel will shadow partially during the day (north side of fireplace).
    Are there REC incentives? Mass is $0.33/kwh (last quarter)

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  • donald
    replied
    I think the reason to use solaredge is future batteries. Especially in California.

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  • emartin00
    replied
    Originally posted by thejq
    Not wanting to confuse you more, but have you considered SolarEdge? At your wattage, SolarEdge will probably be cheaper. From the quotes I've gotten, 4-5KW seems to be the equilibrium point, beyond which SolarEdge scales better as the incremental cost is less.
    That is what I have found as well. I'm looking at doing about a 5kW system and was originally planning to go with micro inverters or AC modules. After looking at the cost of SolarEdge, I'll save almost $1k. And that is for the 300W SolarEdge optimizers, so no clipping at all on 300W modules.

    Leave a comment:


  • sensij
    replied
    Originally posted by 71SoCal
    Yes, it's really just a math problem. I would definitely appreciate any "real world" data. My location info: zip is 92128, roof tilt is 18.5 deg., azimuth is 240 deg. One panel will shadow partially during the day (north side of fireplace).
    For real world data, you might want to review the output of this system on PVOutput.org. There are no 92128 systems in Team San Diego, but the system linked is in 92127 and has LG285's paired with M215's, oriented at 180 deg azimuth with a 22 deg tilt.

    There will definitely be some clipping... May 10th, for example, shows something like what you might expect to see in springtime. The power output in the middle of the day is capped at 6300 W (28 * 225 W).

    Now let's look at what PVWatts would have said about that day. If I enable gridded locations and enter the 92127 zip code for that system, along with 180 deg azimuth, 22 deg tilt, premium, roof mount with 6% loss, and lay the model on top of the actual data from around that time (May 11th, to be exact), we see the following:

    PVWatts Comparison.JPG

    PVWatts seems to have expected a little bit more morning cloud cover than what was actually received that day (and/or higher temps than what actually occurred), but matches the system output in the afternoon very well.

    Now let's use the same method as J.P.M. suggests, and compare the output for the year with and without clipping:

    PVWatts (no clipping): 14608 kWh
    Live system: 14429 kWh
    Difference = 179 kWh

    If we replicate that model on the system being discussed:

    7.7 kW (capped at 225*28 = 6300 W)
    92128
    240 deg azimuth
    18.5 deg tilt
    "premium"
    roof mount
    6% loss

    PWatts (no clipping) = 13771 kWh
    Projected (with clipping) = 13724 kWh
    Difference = 47 kWH

    At 0.20 / kWh, that is worth about $9.40 / annually.

    If you want to use TOU pricing with $0.49 / kWh from 12 pm to 6 pm, it is more like $23 annually.

    I just don't see the financial justification for spending $500 for what is certainly worth less than $50 annually in cost avoided. However, as I think some forum members have shown, there is an emotional component to the decision for many people. "Loss Aversion" is influential in decision making, and many people look at the flat top of a clipped day and freak out, even when accepting that clipping was the better financial decision. For those people, spending the extra $500 might be worth the peace of mind, even if some of us only see money spent for no tangible return.

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  • Alisobob
    replied
    solar71.JPG

    I clip a little with 270 watt Solar World panels, hooked to M215's.

    M250's were a little pricier when I did my install, and I was told I would never recoup the price difference....

    Now? I may have gone with them.

    Its a tough call....

    Leave a comment:


  • J.P.M.
    replied
    Under no shade conditions, if you run PVWatts, choose the hourly output option, download to Excel, and add columns that choose the lesser of (# of panels) X (micro clipping point) or the PVWatts hourly est. and sum over the 8760 hrs, you'll get a SWAG # on clipping penalty by the diff. of the PVWatts output and the clipped total. Do the same for # of hrs. clipping.

    Using that method, at 240 az. and 20 deg. tilt and using std. panels, that method gives me about 4 kWh/yr. penalty over a string inverter over a sporadic 28 hrs. for the M215 if it clips at 225 W, and none for the M250. In this case, because of, and when shading is accounted for, the micros may do better than the string in terms of output.

    Other stuff I wrote gives me about 10 kWh/yr. over 70 hrs./yr. for the M215's and also zero penalty for the M250's, but my stuff is more panel specific, in this case to the LG 275's. Either way, the two methods seem pretty close and consistent to me, without separating too many fly specs from pepper.

    Based on the above estimates, I'd take a guess and say the diff. is so small - M215 to M260 as to be not worth it.

    Leave a comment:


  • 71SoCal
    replied
    Originally posted by sensij
    Finally, someone posting that actually gets it. As J.P.M. suggests, the value of the energy you generate with M250's that would have been clipped may not be much compared to the extra $500 you would be spending. If you share your location and tilt (azimuth = 240)... others can verify your simulations and conclusions.
    Yes, it's really just a math problem. I would definitely appreciate any "real world" data. My location info: zip is 92128, roof tilt is 18.5 deg., azimuth is 240 deg. One panel will shadow partially during the day (north side of fireplace).

    Leave a comment:


  • thejq
    replied
    Sure, I don't disagree with the point that in order to estimate the cost of clipping, you have to properly setup PVWatts and run through a whole year worth of data. Only until then you can be truly convinced. But on the other hand, the difference in $ is so small in the grand scheme of things, and even Enphase doesn't recommend using m215 for > 250W, is it really worth it (time/risk/possible regret)? Of course, it's not my money so it's easy for me to say and you have every right/reason to disagree. Also when setting up PVWatts, for the LG, I would select premium panel and < 4% loss to be more realistic.

    Not wanting to confuse you more, but have you considered SolarEdge? At your wattage, SolarEdge will probably be cheaper. From the quotes I've gotten, 4-5KW seems to be the equilibrium point, beyond which SolarEdge scales better as the incremental cost is less.

    Leave a comment:


  • sensij
    replied
    Originally posted by 71SoCal
    It would be about $500 more to go to M250 (before federal credit). I ran the PVWatts calculator and from reading several threads, I'm under the impression that rarely, if at all, I would clip during the summer for maybe an hour-ish each day. I'm hoping someone will chime in with some data that validates/invalidates my hypothesis.

    Thanks for bringing up the topic. I would definitely consider bumping up to M250's if it could be justified.
    Finally, someone posting that actually gets it. As J.P.M. suggests, the value of the energy you generate with M250's that would have been clipped may not be much compared to the extra $500 you would be spending. If you share your location and tilt (azimuth = 240)... others can verify your simulations and conclusions.

    Leave a comment:


  • J.P.M.
    replied
    Originally posted by thejq
    Assuming $3.5/W, that's $18 out of $962 (average per panel cost) to go from M215 to M250. A rather small price to pay IMO.
    To a greater or lesser extent, that depends on the cost of the electricity not produced. If say, 200 kWh/yr. is clipped at $0.20/kWh, 40 bucks/yr. in lost opportunity may or may not be significant to the owner(s). clipping loss will need to be evaluated and a value assigned to it.

    71SoCal: Tilt/azimuth/zip ?

    Leave a comment:


  • thejq
    replied
    Originally posted by 71SoCal
    I believe it's about $18 more per inverter. From what I've read, the 275w panels will almost never clip with the M215's. My azimuth is 240 degrees, so I don't anticipate pegging the M215 very often, if at all.
    Assuming $3.5/W, that's $18 out of $962 (average per panel cost) to go from M215 to M250. A rather small price to pay IMO.

    Leave a comment:

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