My system will have 16 Full River DC 224 6 volt batteries. Total energy stored 3584aH. So if I ran the batteries down only 30% I would have 1075aH. My inverters seem to max out at 65amps. Dividing 1075/65 gives me 16.5 hours of battery if I was maxing my draw.
Roughly correct?
Edit: I don't care if I'm off by a factor of 20% because of inefficiencies. I'm wondering if I am off by factor of 4 or 5 because I don't get the basics. There I just saved the nitpickers from some keystrokes.
Thanks
Roughly correct?
Edit: I don't care if I'm off by a factor of 20% because of inefficiencies. I'm wondering if I am off by factor of 4 or 5 because I don't get the basics. There I just saved the nitpickers from some keystrokes.
Thanks
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