Actual Solar Panel Watt Capability

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  • PNjunction
    replied
    Was that a PowerWerx inline meter? Nice and handy. I dig mine, although it was a Turnigy. Not as accurate as my Fluke 87V however. As a 130 amp meter, it may not be totally accurate with the calculations at the very low ranges like 2 or 3 amps. A calibrated shunt will tell you. Still a good instrument though.

    What you may also be experiencing is common for batteries that aren't in a moderately discharged state. They charge up rapidly (the battery terminal voltage rises during charging and tries to meet the charge voltage source.) and when it gets close to the panel voltage output (or the voltage limitation of the charge controller), the battery naturally tapers down the current in the "absorb mode". Could THIS be the 35 watts you are experiencing? In absorb, the battery itself is doing the current-regulating (albeit voltage limited by the charge controller and eventually very little current flows.

    There have been a few that have hooked everything up this way with freshly charged batteries and seem to think that their solar setup is bad when they observe a miniscule amount of current flowing - unknowingly because they are immediately into the absorb stage, and not the bulk charge stage.

    We have no way of knowing how that nicad is reacting, and isn't really meant for a cv solar charge controller anyway. I'd perform the test again, but this time with a *FRESH* lead-acid battery that has some amount of discharge to it. An 18 to 22ah sealed agm should be easy to find. Of course this would have to be at your solar-insolation maximum period (somewhere around noon-ish), no clouds/haze, aligned towards the sun etc.

    Going from 35 watts at 18v to the max of 50 watts at 18v is about a calculated 830 milliamp difference. Let's say your panels are on the low end of their stated 3% manufacturing tolerance. Maybe a bit more. Toss in some variance in the accuracy of the powerwerx itself. A bit of loss in the controller....some non-optimal solar-insolation as compared to the manufacturer's STC flash test ....

    I think you are probably doing fine.

    Leave a comment:


  • inetdog
    replied
    Originally posted by Naptown
    Huh?
    I'm sure the OP digested and understands that completely
    My hope was that the OP could at least handle the first paragraph; the rest was just for fun.

    Leave a comment:


  • Naptown
    replied
    Originally posted by inetdog
    Ohm's law is really only useful when the resistance, R, of a circuit element is close to constant. The problem with PV and with any semiconductor device is that R is not a constant over any wide range of current and voltage.
    In the I versus V plot that Dereck mentioned, the slope of the curve at any point (or its inverse, depending on how you draw the curve) is the value of R at that point. Not even close to constant. And even then, that curve is only for one specified light input. There is actually a family of curves, one for each amount of incoming light.
    And, of course, the panel can modeled as the equivalent circuit of a light-dependent current source in parallel with a light-dependent loss resistance. This comes close to modeling the maximum voltage and maximum current limitations that you see, but is messy to work with.
    Or you can model it as a constant voltage source in series with a light-dependent series resistance.
    Huh?
    I'm sure the OP digested and understands that completely

    Leave a comment:


  • inetdog
    replied
    Originally posted by Experimentor
    But it still has to obey Ohms law, no? I am listening.
    Ohm's law is really only useful when the resistance, R, of a circuit element is close to constant. The problem with PV and with any semiconductor device is that R is not a constant over any wide range of current and voltage.
    In the I versus V plot that Dereck mentioned, the slope of the curve at any point (or its inverse, depending on how you draw the curve) is the value of R at that point. Not even close to constant. And even then, that curve is only for one specified light input. There is actually a family of curves, one for each amount of incoming light.
    And, of course, the panel can modeled as the equivalent circuit of a light-dependent current source in parallel with a light-dependent loss resistance. This comes close to modeling the maximum voltage and maximum current limitations that you see, but is messy to work with.
    Or you can model it as a constant voltage source in series with a light-dependent series resistance.

    Leave a comment:


  • Sunking
    replied
    Originally posted by Experimentor
    I get it - it's a current source. But it still has to obey Ohms law, no?
    Sure it does. First look at the IR curves published for solar panels. The portion you want to pay attention too is the vertical line that runs from MPPT Knee down to Zero Volts at Zero Ohms. The current is almost linear. For your panel I am guessing at MPPT voltage the Imp current is 2.9 amps, and at Zero Volts or Isc is 3.1 amps. So what is the Power? It is undefined as it depends on what resistance you are pushing the current through. The highest current possible assuming 100% irradiance input is 2.9 amps so the power is 50 watts @ Vmp of 17 volts.

    But what happens if say we take a 6 volt battery and connect it to the panel. Imp has not changed as it is still 2.9 amps. But we pulled down the voltage from 17 volts to 6 volts. What is the power now? Could it be 17.4 watts?

    What if there is haze in the area, or the panel is not facing directly into the sun so the irradiance has dropped to 50% input. Well since a panel is a current source and the output current is directly proportional to light input our current falls off to 50% or 1.45 amps. Vmp does not change and is still 17 volts, but now Pmax is 25 watts.

    So answer some simple Ohm's Law equations using a constant current source. What is the voltage and power with 2.9 amps throwing through

    0 Ohm
    1 Ohm
    2 Ohms
    3 Ohms
    4 Ohms
    5 Ohms
    5.94 Ohms

    Now here is where magic happens with a solar panel When you go above MPP voltage, the panel now turns into a voltage source up to 22 volts at Open Circuit infinite ohms. So when at 21 volts what is the power and current at 20 ohms?

    Run through those equations may shine some light in a place you have never seen before.

    Leave a comment:


  • t5800512
    replied
    I'm thinking you may not be testing under ideal conditions. There are many things to consider. Sun Radiance may not have been considered. I know with my Solar array, I see a difference in output due to dust and smog that is not even discernible to my eyes. I know this because after a good air cleaning rain my output goes up even at the same temperatures. If you are in Germany, your radiance will be lower than places south of you. Just saying.

    Leave a comment:


  • Experimentor
    replied
    Originally posted by Naptown
    The other thing missing from the op' s post would be cell temperatures.
    If say he were in a hot climate and the cell temp was say 50c in most panels that would equate to almost 25% less power. ( most panels lose .44% per degree above 25c)

    Now to truly test you need to know cell temperature and calculate the losses from that in also

    Did your test equipment include a pyronometer? If not how do you know how far off the lighting is or if you are indeed getting the 1000w per sq meter irradiance.
    No, it didn't include a pyronometer. I was limited to doing it on a clear sunny, but cool day, low humidity with the panel held directly facing the sun. I would imagine I can't get much better results than that other than in a lab. Like I said, I would have expected a 10% difference in theoretical and actual capacity, but not a 30% difference.

    Leave a comment:


  • Experimentor
    replied
    Originally posted by t5800512
    Yep, Sunking is brutally honest, and a little lacking on people skills. But he is usually right.

    I don't want to get into the measurement aspect of this discussion. All I will say is that the true output would be better represented as a curve than a straight line.

    So, there are many ways to measure the output of a PV panel. And of coarse manufactures do it under ideal laboratory conditions that do not indicate real world conditions. There are two rating to look at, STC and PTC. The STC rating is more that perfect lab test that the manufactures use. But PTC will get you closer to real life conditions (but still not spot on perfect). You should be looking for the PTC rating. Many manufactures do not offer the PTC ratings for obvious reasons. But for many of the panels without OEM ratings, the PTC has been measured and listed at sights like: http://www.solardesigntool.com/compa...s-modules.html

    Another good link that does a better job of explaining what I just tried to explain is: http://www.civicsolar.com/forum/1036...-and-solar-ptc.

    But until government steps in and forces PV panel manufacturers to conform to some standards, it is kind of the honor system, and ratings get fugged.
    Thank you for your civilized answer and the useful links.

    Leave a comment:


  • Experimentor
    replied
    I'm 50. Wow, wrong on something; that probably hurts. I get it - it's a current source. But it still has to obey Ohms law, no? I am listening. Why do you think I keep asking questions? Perhaps your answers are not correctly tailored to my questions?

    By the way, the temp is less than 25C.

    Leave a comment:


  • Sunking
    replied
    Originally posted by Naptown
    The other thing missing from the op' s post would be cell temperatures.
    If say he were in a hot climate and the cell temp was say 50c in most panels that would equate to almost 25% less power. ( most panels lose .44% per degree above 25c).
    He is in Germany and has never seen anything above 30.

    Leave a comment:


  • thastinger
    replied
    OP, how is the panel oriented azm and ele.

    Leave a comment:


  • Sunking
    replied
    Originally posted by Experimentor
    Wow,
    Everyone here is a know-it-all. Sinus is how it's pronounced in German. Sorry I waxed to a different language there. Your link doesn't contradict Ohms law, does it? And there's a difference between being molly-coddled and just being rudely flamed. I came to the forum as an admitted solar newbie and what a welcome I get. Sorry I bought a couple of panels without seeking this forum's approval first.

    Sunking: You can only have zero resistance in a theoretical circuit. Even experimental super-cooled circuits have some resistance.

    I acknowledged an understanding that a controller is going to pull down the panel voltage to the battery voltage. Did you notice I mentioned connecting the panel directly to a higher voltage, low resistance battery pack without a charge controller? Though I don't claim to know as much as some people, the way I understand electrical theory, if a panel is truly capable of 50 watts, with this uncharged battery it should go to the maximum voltage capability (18 volts) and the maximum current (2.78 amps). As I said, that showed, again, that it was only 35 watts. So as I understand it, the actual capacity of the panel is 35 watts. If you can actually explain why I am wrong, instead of just flaming me, I would appreciate it.
    Like I said, I would have expected a 10% difference in theoretical and actual capacity, but not a 30% difference.
    Like I said you do not understand current sources period. A solar panel is a Current Source. Until you understand current sources you will never figure out what is going on. I can help you, but you have to pull your head out of the sand and be willing to learn and listen. I am a professional licensed engineer with 33 years of experience and know what I am talking about. My bet is you are not even 33 years old. I might know something you do not and can teach you something. Right now you do not want to learn or listen. That is not our problem but yours alone.

    Leave a comment:


  • Naptown
    replied
    The other thing missing from the op' s post would be cell temperatures.
    If say he were in a hot climate and the cell temp was say 50c in most panels that would equate to almost 25% less power. ( most panels lose .44% per degree above 25c)

    Now to truly test you need to know cell temperature and calculate the losses from that in also

    Did your test equipment include a pyronometer? If not how do you know how far off the lighting is or if you are indeed getting the 1000w per sq meter irradiance.
    Last edited by Naptown; 08-29-2013, 01:55 PM. Reason: Added stuff

    Leave a comment:


  • Experimentor
    replied
    Wow,
    Everyone here is a know-it-all. Sinus is how it's pronounced in German. Sorry I waxed to a different language there. Your link doesn't contradict Ohms law, does it? And there's a difference between being molly-coddled and just being rudely flamed. I came to the forum as an admitted solar newbie and what a welcome I get. Sorry I bought a couple of panels without seeking this forum's approval first.

    Sunking: You can only have zero resistance in a theoretical circuit. Even experimental super-cooled circuits have some resistance.

    I acknowledged an understanding that a controller is going to pull down the panel voltage to the battery voltage. Did you notice I mentioned connecting the panel directly to a higher voltage, low resistance battery pack without a charge controller? Though I don't claim to know as much as some people, the way I understand electrical theory, if a panel is truly capable of 50 watts, with this uncharged battery it should go to the maximum voltage capability (18 volts) and the maximum current (2.78 amps). As I said, that showed, again, that it was only 35 watts. So as I understand it, the actual capacity of the panel is 35 watts. If you can actually explain why I am wrong, instead of just flaming me, I would appreciate it.
    Like I said, I would have expected a 10% difference in theoretical and actual capacity, but not a 30% difference.

    Leave a comment:


  • t5800512
    replied
    Yep, Sunking is brutally honest, and a little lacking on people skills. But he is usually right.

    I don't want to get into the measurement aspect of this discussion. All I will say is that the true output would be better represented as a curve than a straight line.

    So, there are many ways to measure the output of a PV panel. And of coarse manufactures do it under ideal laboratory conditions that do not indicate real world conditions. There are two rating to look at, STC and PTC. The STC rating is more that perfect lab test that the manufactures use. But PTC will get you closer to real life conditions (but still not spot on perfect). You should be looking for the PTC rating. Many manufactures do not offer the PTC ratings for obvious reasons. But for many of the panels without OEM ratings, the PTC has been measured and listed at sights like: http://www.solardesigntool.com/compa...s-modules.html

    Another good link that does a better job of explaining what I just tried to explain is: http://www.civicsolar.com/forum/1036...-and-solar-ptc.

    But until government steps in and forces PV panel manufacturers to conform to some standards, it is kind of the honor system, and ratings get fugged.

    Leave a comment:

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