How to calculate the capacity of storage battery?

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  • maxi_da1
    replied
    100MW wind farm

    Guys i am working on design of a 100 MW wind farm and i need to know the calculations about energy storage of the system using batteries?

    Precisely speaking,

    What kind of batteries should be placed ?
    What should be the ratings of battery in terms of power output in times of high demand.(Power out to the grid)

    Please help me

    Leave a comment:


  • russ
    replied
    Originally posted by Naptown
    There is no place on the planet that gets 10 sun hours a day. You are confusing daylight hours with sun hours.
    When panels are tested they are exposed to a light = 1000W per square meter. that gives them the watts of the panels.
    Sun hours are the calculated amount of light in watts per square meter /1000.
    Mike gave you a link to find the sun hours for your area. use it to find the sun hours for the lowest month of your year at your location and use that number to calculate how many watts of panels needed.
    Except NREL uses the term 'insolation' which is generally kW/m2/day

    To dumb it down people all the insolation value sun hours. 5.5 kW/m2/day is sometimes referred to as 5.5 sun hours

    Leave a comment:


  • Naptown
    replied
    There is no place on the planet that gets 10 sun hours a day. You are confusing daylight hours with sun hours.
    When panels are tested they are exposed to a light = 1000W per square meter. that gives them the watts of the panels.
    Sun hours are the calculated amount of light in watts per square meter /1000.
    Mike gave you a link to find the sun hours for your area. use it to find the sun hours for the lowest month of your year at your location and use that number to calculate how many watts of panels needed.

    Leave a comment:


  • tharun
    replied
    Originally posted by Mike90250
    Anyway, you need to harvest 300 watt hours, divide by ____ sun hours = ______ watts of PV
    First of all, thank you mike. Really thank you. You cleared my mind.
    lets say in here we have 10 sun hours. so i should buy a 12 volt 30 watts panel?

    Leave a comment:


  • Mike90250
    replied
    welcome. Lets' un-confuse this a bit.

    power consumed by the fan is 50watts.
    power required = 50 watts * 3 hours = 150watt hours
    Good so far. If you use only 50% of battery, then you need a 300 watt hour battery.
    At 12V, that would be a 25amp hour battery.

    Now to recharge that battery, to account for all the system losses, you need to have a PV panel with a wattage nameplate that, when multiplied by your SUN hours
    use PV watts to find out your hours http://www.nrel.gov/rredc/pvwatts/about.html
    Ths solar SUN hours are quite different than when the sun is up , most areas get 6 or fewer hours.

    Anyway, you need to harvest 300 watt hours, divide by ____ sun hours = ______ watts of PV

    If you use an inverter , add 30% to the needed 300W harvest, you will need to harvest about 400 wh

    Hope this helps
    Last edited by Mike90250; 04-22-2012, 10:26 AM.

    Leave a comment:


  • tharun
    replied
    need help.. confusing

    which is ri8.. case1 or case2?
    CASE I:
    our fan needs 220 v and 0.2 A for an hour = 50 watts.
    a 12volt 7AH battery @20 hour rate -> 7/20 = 0.35 A.
    The battery can sustain a 0.35A load for 20 hours.
    But we can use only the 50% capacity of battery so tat it doesnt get damaged.
    So 0.35A load for 10 hours.
    If we consider the losses in invertor, the time will be around 3 hours.
    CASE II:
    power consumed by the fan is 50watts.
    lets consider that we want the fan to run for about 3 hours in battery.
    power required = 50 watts * 3 hours = 150watt hours
    So, the battery capacity should be 150 watt hours.
    what we need : Two 12volt 7AH in parallel. (in parallel v is constant and I= 7+7, so P=12*14=168 watt hours)
    Loses in invertor will occur. We can not drain the full power from the battery.

    Leave a comment:


  • Mike90250
    replied
    It's a giodeline to start. Same batteries, same site, but more batteries, sized to only 20% dishcarge, should last over 5 years. (Deep cycle batteries, not Kmart deep/starter batteries)

    Leave a comment:


  • FamilyCamper
    replied
    Originally posted by Mike90250
    Right, battery cycles, are:
    a) Discharge to some value
    b) Recharge back to full
    = one cycle

    Not the same thing as AC powerline frequency (cycles)
    So with that said that means that the average battery coming in with a 50% discharge would last less than a year?

    Leave a comment:


  • Mike90250
    replied
    Originally posted by MarineLiner
    so it differs with "cycle" in the AC (Alternative Current, Hertz/cycle).
    and Depth of Discharge (DOD) is what i just know.
    Right, battery cycles, are:
    a) Discharge to some value
    b) Recharge back to full
    = one cycle

    Not the same thing as AC powerline frequency (cycles)

    Leave a comment:


  • MarineLiner
    replied
    Cycles vs Life

    Originally posted by Mike90250
    Batteries have a shorter life, the deeper you discharge them. example:
    1000 cycles 10% discharge
    800 cycles 20% discharge
    300 cycles 50% discharge
    80 cycles 90% discharge
    Generally, discharge to no less than 50%, and size 1 day to about 10%
    .....
    Then you have to recharge it with something.
    Last edited by MarineLiner; 07-17-2009, 11:35 PM.

    Leave a comment:


  • Mike90250
    replied
    Originally posted by solarf.helen
    hi, Mick90250,

    I want to make an off-grid system, I need to figure out which capacity of battery I should use.

    Ok, let me make an example,
    Load :2* 11W lamp; 10 hours working time per day.
    system voltage:12V
    Rainy days: 3 days

    Then how will you calculate the capacity of the battery?
    Much better question. I knew you were not going to manufacture a battery.

    Batteries have a shorter life, the deeper you discharge them. example:
    1000 cycles 10% discharge
    800 cycles 20% discharge
    300 cycles 50% discharge
    80 cycles 90% discharge

    Generally, discharge to no less than 50%, and size 1 day to about 10%

    You are asking for 3 days. I 'll assume 12V CFL, so no inverter losses

    Your load is 22W for 10 hrs = 220W hour x 3 days = 660w hour consumed in 3 days

    So a battery bank of 1320wh would be the minimum size.

    Working all in watts, allows conversion back to any voltage. Volt x Amp = watts

    12V = 110A
    24V = 55A

    So a standard group 24 size battery would be just under the spec, but a group 27 would

    just make it. at 105A.

    Then you have to recharge it with something.

    Leave a comment:


  • solarf.helen
    replied
    hi, Mick90250,

    Thanks for your answers, but I think you did not catch what I said. You know if I want to make an off-grid system, I need to figure out which capacity of battery I should use.

    Ok, let me make an example,
    Load :2* 11W lamp; 10 hours working time per day.
    system voltage:12V
    Rainy days: 3 days

    Then how will you calculate the capacity of the battery?

    Leave a comment:


  • Mike90250
    replied
    The battery manufacturer makes that calculation when they design the battery, and then they put a label on the battery with the specs.

    example 12V 110Ah @ 20 hour rate


    In reality, you can only use half the power stored, otherwise, you severely shorten the life of the battery. There is a good battery FAQ here:
    http://www.windsun.com/Batteries/Battery_FAQ.htm That will answer a lot of questions I hope.

    Mike

    Leave a comment:


  • How to calculate the capacity of storage battery?

    In stand alone solar system, how do you calculate the capacity of storage battery? Is that any formula?

    Please make an example. Thanks so much for any answers.

    Helen
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