1.23V-30V DC-DC Buck Converter Step Down
Try this title search, 121258718860 good example I have used. Bruce Roe
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Another idea: Solar-Powered Camera
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Switching regulator
quality stuff and a lot of my supply. But likely a running switcher can be picked up for like $3 on
Eb+y, check it out. Bruce RoeLeave a comment:
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nice power energy-conservation ip cameras,i often buy bull **** (mofified by Russ) in handgiftbox before,so i need to search some solar-cameras now.lol
Mod note - next funny link you are gone.Leave a comment:
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Yes. My 20 watt panel powers a Rule 360 Bilge pump to move water through a homemade collector to heat the pool. It's just a little inflatable kids pool. The water flow seems pretty good. My collector is just some garden hose pained black. I'll probably add some glazing and more hose to it soon.
Could I put my 20w collector to better use doing something else?Leave a comment:
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"Running the solar heater" = powering the pump in a solar heat system, not supplying the heat itself. Still not clear how much water a 20 watt pump can move though.Leave a comment:
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Nope, not good at all. Guess I'll invest in a cable to power the camera. Thanks for figuring that out though.
And I guess I'll demote the current 20 watt panel I already have to running a homemade solar heater for my daughter's swimming pool. It seems to pump water pretty well with the 12v bilge pump I have it hooked up to.Leave a comment:
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Maine huh? Not good.
Panel wattage = 120 watts
Battery Capacity @ 12 volt = 50 AH (AGM format, FLA will not work for this application, charge rate too high)
PWM charge controller AMPS = 10 Amps
FWIW if located in Tuscon AZ
Panel wattage = 30 watts
Battery = 50 AH
Pwm Charge Controller = 5 amps.Leave a comment:
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zip is 04769. Thanks!Leave a comment:
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Maybe I should think about burying a power cableLeave a comment:
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I am being lazy today but I see some problems, mostly in the 7805 regulator. The 7805 is a series voltage regulator. What that means is the Input Current = Output current which is real bad news for solar systems. That is why PWM controllers suk.
OK you camera use 2 watts @ 5 volts which means the current is .4 amps. So the battery is @ 12.5 volts supplying .4 amps to the 7805 regulator, and the regulator output is 5 volts @ .4 amps. See the problem?
Well here is the problem your battery is supplying 12.5 volts x .4 amps = 5 watts, while you are only using 2 watts. That means you are burning off 3 watts on the regulator as heat. No problem for the regulator as it is designed to do that but is a huge waste of energy.
Normally one would calculate the camera daily usage as 2 watts x 24 hours = 48 watt hours. However that is not a true statement because the real consumption is 5 watts x 24 hours = 120 watt hours.
If you were to use 48 watt hours and your area Solar Insolation is 3 sun hours in winter you would use a 30 watt solar panel, and a 12 volt 20 AH battery. When in reality it should be a 80 watt solar panel and a 50 AH battery.
So if you used the 48 watt hour figure to design by, it would fail on the 2nd or 3rd day never to come back on.Leave a comment:
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