I have a 690 amp hour battery bank (6 of the 6volt 230 ah golf cart batteries run in series parallel with bus bar and equal length 0/2 gauge pure copper cable), 1,200 watts of solar panels (12 of the Renogy 100 watt panels), a Midnite Solar Classic 150, and I plan on using almost all dc powered stuff with the power inverter now being limited to under 1,000 watts of usage (or less).
Decreasing amp draw of an electric element
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I have a 690 amp hour battery bank (6 of the 6volt 230 ah golf cart batteries run in series parallel with bus bar and equal length 0/2 gauge pure copper cable), 1,200 watts of solar panels (12 of the Renogy 100 watt panels), a Midnite Solar Classic 150, and I plan on using almost all dc powered stuff with the power inverter now being limited to under 1,000 watts of usage (or less).
Example you used 6-volt 230 AH batteries which is fine if you needed a 230 AH battery at 36 volts, Instead being trapped inside a 12 volt box, you used 12 volts. To do that you had to make sacrifices, and workaround the problems and extra expense that creates like using a Buss Bar and 3-pairs of of 2/0 AWG cable. Lot of bad things are going to happen with that choice like cutting your battery cycle life in half. You are going to be replacing those batteries in a year or two.
Those 6-volt 230 AH batteries I am guessing are Duracell Golf Cart batteries or similar and can deliver up to 35 to 40 amps before voltage drop exceeds 2% only leaving you 2% allowance for cable loses between batteries and Inverter. 2% of 12 volts = .25 volts and another .25 volts for cable losses. At most your batteries and set up can only supply a 1000 watt load and at that high of a discharge rate turns your 230 AH battery into 180 AH batteries or only 70% as much as you thought you had. You did not take any of that into account and is creating the headaches you are having.
No you want to compound your errors, and only want to hear that wil work. It is not going to work, and anyone telling you it will work is wrong or lying to you. So your water heater is designed to heat water with 1400 watts. Using a conservative estimation will run 1 maybe 2 hours per day. So let's sugar coat it and pretend 1 hour per day at 1400 watts or 1400 Watt hours. Initially you might think if you reduced power by 75% down to 350 watts all your troubles are over and all it means instead of 1 hour run time is now 4 hours run time. Nothing could be further from the truth no one has the guts to tell you. That heater is designed to run at 1400 watts. If you force it down to 350 watts is going to take a lot longer than 4 hours because you are ignoring thermal losses. At 350 watts is not likely enough power to heat the water to a high enough temperature to allow the thermostat to turn the power off, or have to run a lot longer than you expect. You are throwing more energy away compounding efficiency issues running 12 volts.
If you had added up all your daily energy needs, and sized thing correctly to begin with, you would have known instantly your battery capacity is undersized. If that water heater uses 1400 watt hours per day, which is unrealistic and uses more than that, you would have known the water heater uses more than 25% of your battery capacity in a day when Peukert Factor is accounted for. You've already exceeded you daily limit in just the water heater alone.
I know you do not want to hear this, too bad I am not politically correct (a forked tongue liar). I will tell you the truth and not gloss over anything. What I can tell you is you can correct the problem to some degree. Buy two more batteries like you have, configure them for 48 volts (all in series), and get a 2000 watt 48 volt Inverter for you to grow into. Keep in mind even at 48 volts, you are still pushing your system to its maximum limits. and even though the batteries label indicates you have a 48 volt 230 AH battery is really a 48 volt 160 AH battery with a 1400 watt load (aka C/6 discharge) .
Your minimum size battery has to meet two objectives, and use the worse case scenario.
1. Max discharge rate not to exceed C/8. With a 2000 watt Inverter requires a minimum:
340 AH @ 48 volts
680 AH @ 24 volts
1360 AH @ 12 volts.
2. Minimum 5 Day Reserve Capacity. So if that water heater only ran 1-hour per day is 1400 watt hours, so a 7000 watt hours. So you would need:
150 AH @ 48 volts
300 AH @ 24 volts
600 AH @ 12 volts.
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Worse case is numero uno, 340 AH @ 48 volts.
With that battery comes minimum charge requirement of C/12 or 1400 watts of panels and at 48 volts is a 30 amp charge controller. Not a 96 amp controller you have now.MSEE, PEComment
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Sunking, if you actually read the posts in this thread, you would see that the novel you just posted is completely irrelevant to the OP at this point. This system has changed.CS6P-260P/SE3000 - http://tiny.cc/ed5ozxComment
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Sunking, if you actually read the posts in this thread, you would see that the novel you just posted is completely irrelevant to the OP at this point. This system has changed.
I appreciate the pointers on making this a more ideal set up able to power more then I'm realistically going to need. I got the extra panels and the 6 volt batteries (I had 6 of the 12 volt batteries before) to try and make things work that I knew going into things were problematic.Comment
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Just ordered a 1200 watt inverter with automatic transfer switch (my manual transfer switch will bypass this for the water heater). Good thing about this is that it will make the outlets hot that are now only functioning when the inverter are on. I'll sell the 2000 watt inverter on Ebay.Comment
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