A 50W panel is rated for about 2.7A. If you are using 26.3Ah per day, 26.3ah / 2.7A / .67 inefficiencies = 14.5 hours. Sorry, won't work.
Are you doing this in winter? Where are you? I'll assume pretty bad sun conditions for winter for 2.5 sun hours. Depending on where you are and when you are doing this, you may be better. 26.3Ah / 2.5 sun hours / .67 inefficiencies = 15.7A. x 12V = 188W panels.
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So would 35AH battery be enough? And how long would it take recharge with a 50W panel? and a 12/24V 30A
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OK, again, as inetdog said, make a loads list. You are all over the place.
Load Amps(A) x Hours = Amp hours (Ah)
Motor1 3.2A x 1 hour = 3.2Ah
Motor2 5.5A x .3 hour = 1.65Ah
Microcontroller 1.16A x 5 hour = 5.8Ah (14W / 12V = 1.16A)
Inverter 0.5A x 5 hour = 2.5Ah (6W / 12V = .5A)
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13.15Ah / 50% depth of discharge = 26.3Ah per day
That's assuming you are beating the heck out the battery, and don't care if it lasts longer than 5 months, and recharging it fully each dayLeave a comment:
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Yeah it essentially equates to 4AH. The motors are run very intermittently and their invidual ratings are (Imax=4.6amps, and 6amps) and are each 12V. The motors pretty much would not run for more than 2 minutes each time and like I said I don't see us running them for 60 mins each a day.
The actuator takes 51 secs to go from one extreme to another. so I bumped it to 1min back and 1 min forth.
The motor is 5rpm.
Actuator: http://www.amazon.com/Stroke-Linear-...inear+actuator
Isn't 100AH a bit excessive. How do you figure i need that much? I was gonna buy 35AH and call it a day especially since the most constant load on the battery would be put on for 5 hours straight a day at most and it would be a 14W controller plugged into a 200W (6W idle) inverterLeave a comment:
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Start with the off-grid design calculator from one of the sticky threads. Although it is most often used for much larger systems, it should work just fine for you.
To ask questions and understand the answers, you need to get one thing about the terminology.
The measure of current is the Amp (A). If a 3A load runs for 2 hours, that is a total load of 6 Amp hours (AH).
If the voltage is a constant 12V, then the energy consumed is 72Watt-hours.
The capacity of a battery is measured in AH, so your statement about 20AH over 5 hours being 4AH does not compute. A load of 4A continuous over 5 hours would be 20AH. And to work well with that load, you should have about a 100AH battery.Leave a comment:
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Walmart Everstat 24DC 101AH for DIY Solar build (flooded lead acid)
Hey guys I am trying to do a DIY MPPT solar project for my senior design. I would need a battery for 5 months. I orginally was going to use this 35AH battery from amazon: http://www.amazon.com/UPG-D5722-Seal...s=35ah+battery But some people told me it wasn't going to be enough
So I started looking at http://www.walmart.com/ip/EverStart-...ttery/20531540 which is a 101AH Flooded lead acid battery.
However some have said it is not the right battery for an application like this so I wanted to ask you guys.
I don't think I need something as big as that battery. With some recaluations for worst case scenario, I estimate a need of 20AH over a span of 5 hours, so approximately 4AH. this would be for each day.
The load:
I plan on connecting a modified sine wave inverter (6W idle overestimated), microconytoller (14W max) that will be attached to the inverter, an actuator (motor 1), and rotisserie motor (motor 2).
motor1 draws 3.2A and motor2 draws 5.5A (both run 12V). For both motors they will only be on when they need to be turned.
Motor1 when on will run for 2 mins each time (1 min to slide up, 1 min to slide down) I would prbly do this at most 30 times a day for experiments
Motor2 is 5rpm so at absolute most I'm gonna have it on for 20 mins a day.
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