My apologies for what must seem like a knucklehead question but I'm extremely new to this. I want to get an idea of whether my newly installed system is producing about what would be the expected output of watts in regards to offsetting my electrical consumption. I live in Palm Springs in the southeastern California desert where cloudy days are headlines in the local newspaper. My contractor installed a SolarEdge SE7600A-US inverter, thirty LG Mono-X LG335S2W-G4 modules rated at 335 watts each, and an equal number of SolarEdge P400 optimizers. All of the equipment is brand new (installed just over a week ago). The modules are mounted on a flat roof at what I believe is a 7 degree tilt, all facing south. Shading is never an issue. My assumption is that the rated output of the setup is 10,050 watts out of the modules under optimum conditions.
What I cannot figure out, at least so far, is what I might expect in terms of AC power production into the Southern California Edison grid. I am aware that maximum output in watts right out of the panels is rarely going to be hitting the 335 watt mark, and I am aware that there are all sorts of losses along the line from the modules to my electrical panel due to the conversion and all sorts of other issues. But on a bright clear late summer's day around 12:30pm, what might I expect in terms of AC power output as measured in watts? The last time I checked under these conditions, the "Pac[W]" (AKA "Power Prod" on another screen) reading on my inverter's display was 7,744, which I assume is what's used to reduce the amount of juice I'm paying Edison dearly for. If that's the case, and if the conditions I've described are pretty decent for production purposes, then is "maximum AC output in watts under best case conditions = 0.75 x total rated module DC output in watts" a standard rule of thumb? I'm just looking for a ballpark figure here. If 7.7 Kw from this system around noon is within the expected range, then I'm happy. Should I be happy?
Thanks,
Nick in Palm Springs
What I cannot figure out, at least so far, is what I might expect in terms of AC power production into the Southern California Edison grid. I am aware that maximum output in watts right out of the panels is rarely going to be hitting the 335 watt mark, and I am aware that there are all sorts of losses along the line from the modules to my electrical panel due to the conversion and all sorts of other issues. But on a bright clear late summer's day around 12:30pm, what might I expect in terms of AC power output as measured in watts? The last time I checked under these conditions, the "Pac[W]" (AKA "Power Prod" on another screen) reading on my inverter's display was 7,744, which I assume is what's used to reduce the amount of juice I'm paying Edison dearly for. If that's the case, and if the conditions I've described are pretty decent for production purposes, then is "maximum AC output in watts under best case conditions = 0.75 x total rated module DC output in watts" a standard rule of thumb? I'm just looking for a ballpark figure here. If 7.7 Kw from this system around noon is within the expected range, then I'm happy. Should I be happy?
Thanks,
Nick in Palm Springs
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