We have 2 of the SB5000US model of inverters and are preparing our installation but are bit confused with the diagrams for the AC hookup to the Main distribution panel. In the documentation it indicates 50A breakers per inverter. I can understand this if it was a 208V AC and a SB7000US but for a 240V and a SB5000US with a maximum of 24A of Maximum Continius Output current, wouldn't a 30A fuse be needed or should we still use a 50A fuse because the Maximum Outout Overcurrent Protection is 50A or do you use the ?
Can you please clarify the situation ?
Can you please clarify the situation ?
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